2[(x-3)+(x+3)]=2(2x)

Solution for 2[(x-3)+(x+3)]=2(2x) equation:

Simplifying
2[(x + -3) + (x + 3)] = 2(2x)

Reorder the terms:
2[(-3 + x) + (x + 3)] = 2(2x)

Remove parenthesis around (-3 + x)
2[-3 + x + (x + 3)] = 2(2x)

Reorder the terms:
2[-3 + x + (3 + x)] = 2(2x)

Remove parenthesis around (3 + x)
2[-3 + x + 3 + x] = 2(2x)

Reorder the terms:
2[-3 + 3 + x + x] = 2(2x)

Combine like terms: -3 + 3 = 0
2[0 + x + x] = 2(2x)
2[x + x] = 2(2x)

Combine like terms: x + x = 2x
2[2x] = 2(2x)

Remove brackets around [2x]
2 * 2x = 2(2x)

Multiply 2 * 2
4x = 2(2x)

Remove parenthesis around (2x)
4x = 2 * 2x

Multiply 2 * 2
4x = 4x

Add '-4x' to each side of the equation.
4x + -4x = 4x + -4x

Combine like terms: 4x + -4x = 0
0 = 4x + -4x

Combine like terms: 4x + -4x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.